Then you can run a fairly simple query: select t. Syntax For DATEDIFF DATEDIFF( <date_or_time_part>, <date_or_time_expr1>, <date_or_time_expr2> ) For minus sign <date_expr2> - <date_expr1> Arguments For. Snowflake supports a single DATE data type for storing dates (with no time elements). There are also consideration of different rules for different countries governing how Daylight Savings Time are calculated, and sometimes the rule changes too. Go to snowflake r/snowflake • by terminal_bound. If the value is a non-integer numeric value (for example, FLOAT) the value will be rounded to the nearest integer. The syntax for using the DATEDIFF function in Snowflake and Amazon Redshift, and Databricks looks like the following: datediff (< date part >, < start date / time >, < end date / time >) A note on Databricks: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. はじめに Snowflake の 日時（日付、時刻含む）について 少しづつだが、まとめておく。 目次 【1】日時（日付、時刻含む）のデータ型 【2】現在日時を返す関数 【3】日時（日付、時刻含む）の変換 1）キャスト 2）DATE_FROM_PARTS関数 【4】日時の計算 1）DATEADD関数 2）DATEDI…Snowflake does not allow to run session variable statement and dashboard query statement together. 2. approx_percentile_estimate. datediff (part: str, col1: Column | str, col2: Column | str) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. If you have extra questions about this answer, please click " Comment ". 0. how can this be achieved? Like select VAR_DATE = DTAE1 from (select date1 from table1 where date1 = 'xxx') Please note that my result set returns only one row. Snowflake Events. See also: TIMEDIFF, TIMESTAMPDIFF Syntax For DATEDIFF DATEDIFF( <date_or_time_part>, <date_or_time_expr1>, <date_or_time_expr2> ) For minus sign <date_expr2> - <date_expr1> Arguments For DATEDIFF: date_or_time_part The unit of time. dates from the DATEDIFF() 1. Hi @SQL Baby , Last Day of previous month：. g. 0 as shown in this following script: SET @TotalTimeDiff = ( SELECT DATEDIFF (SECOND, ( SELECT CONVERT (TIME, @DateFrom) ), ( SELECT CONVERT (TIME, @DateTo) )) / 3600. From fetching the current timestamp to calculating date differences, we've got you covered. O sinal de menos ( -) também pode ser usado para subtrair datas. BUT now I'm trying to code like this: coalesce (datediff (day, to_date (datvr::varchar, 'YYYYMMDD'), to_date (datvrn::varchar, 'YYYYMMDD')), 0) DAYSTONEXTPO. approx_percentile_estimate. Trying to get the "native"/NTZ time from a timestampntz field. WHERE (CREATED_AT::DATE BETWEEN (CURRENT_DATE::DATE - INTERVAL '1 WEEK') AND CURRENT_DATE::DATE). By submitting this form, I understand Snowflake will process my personal information in. Thanks! Expand Post. here is one. 124 seconds. > Snowflake Forums. 함수 참조. In terms of indexing capabilities, Databricks offers hash integrations whereas Snowflake offers none. Alias for DATEADD. 0 to 59. snowflake. If a non-integer decimal expression is input, the scale of the result is inherited. Again, the expected results would be a value of 1. For example, DATEDIFF(milliseconds, '00:00:00', '00:00:01. Add a comment. To change the rounding mode to round the value half to even (e. So try converting one of them to other timezone using "CONVERT_TIMEZONE" and thn apply the DATEDIFF function. I assume that this happens due to the /sum(iff(iscode=1,1,0)) where this presumably sometimes returns 0. Databricks, on the other hand, has a market share of 8. initial_proposal_completed)/ 60 / 24-sum (case when IsSalesWorkday = 0 then 1 else 0 end) diff. To run a stored procedure inside a transaction, you. functions. DATEDIFF. The collation specifications of all input arguments must be compatible. For the second record, it. snowflake. Add a comment. The offset is measured in: The number of UTF-8 characters if the input is VARCHAR. To build a calendar table, you don't have to start from scratch, you can use the below query to build a Calendar table in Snowflake. Extracts the specified date or time part from a date, time, or timestamp. 2 Answers. : create temp table dummy_1 (days int) as select datediff ('day', '2018-07-20', '2018-07-27'); 2. Improve this answer. array_aggThe Snowpark library provides an intuitive library for querying and processing data at scale in Snowflake. Snowflake passing parameters. No exemplo a seguir, o parâmetro TIMESTAMP_TYPE_MAPPING é definido como TIMESTAMP_LTZ (fuso horário local). An alternative sql only solution - start and end dates go into the current_date() spots. 이 함수는 연도, 분기, 월, 주, 일, 시간, 분, 초, 밀리초, 마이크로초, 나노초 단위를 지원합니다. Converting Valid Character Strings to Dates, Times, or Timestamps. The DATEDIFF() function returns an integer that represents the number of days between two dates. In Snowflake, it is possible to run stored procedures within a transaction, which means that the changes made by the stored procedure are committed or rolled back as a single unit of work. For example, if we want to get the name ‘John’ from the name ‘John Rose’, then we can make use of this function as: substring (‘John Rose’,0,4). I consent to my information being shared with Event Partners in accordance with Snowflake’s Event. g. I tried to define the correct start date with a SQL CASE before i start the AVG(DATEDIFF). snowflake. : you're comparing dates with timestamps, and not whole days), you can simply convert two date or timestamp strings in the format 'YYYY-MM-DD HH:MM:SS' (or specify your string date format explicitly) using unix_timestamp(), and then subtract them from each other to get the difference in seconds. runs in 202msUsage Notes. You can use the SWITCH statement form of CASE thus you just need to branch the options you want, and matching one will be used. For ' integer ' (a string containing an integer), the integer is treated as a number of seconds, milliseconds, microseconds, or. An aggregate function always returns exactly one row, even when the input contains zero rows. schemaname; CREATE table objectname. Window functions operate on windows, which are groups of rows that are related (e. snowpark. 5 years ago. Both Databricks and Snowflake implement cost-based optimization and vectorization. #sql. (varchar(10),(DATEDIFF(s,A. Presumably, by business day, you mean Mon-Fri. checkin_date, '2018-08-01') <= 90, 1, 0)) as visits_past_90_days, from user_checkin as uc where uc. DATETIME. to round -0. In SQL SERVER, you can use the following query (replace the date with your field): SELECT CASE WHEN datediff (year, '20120303', getdate ()) > 1 THEN datediff (year, '20120303', getdate ()) ELSE datediff (day, '20120303', getdate ()) END AS Diff. It can be one of the following formats: Year:. TIMEADD. 2. I guess first I need to find "min_data" for value, then "next_date" and calculate "DATEDIFF". When calculating it, only from 9am till 17pm and weekdays are needed to be accounted. – Simeon Pilgrim. 0. You should add another column to indicate the type of count you're calculating, but you can accomplish this with datediff,last_day, and date_trunc(to get first of month). Similarly, if two queries run concurrently on the warehouse for the same 20 minutes, Snowflake will bill for 20 minutes, not 40. snowflake. String constants must always be enclosed between delimiter characters. Like Liked Unlike Reply. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go. 0. The function will always. SELECT AVG (CAST (DATEDIFF (d, DateUsed, DateExpires) AS FLOAT)) FORM tbl. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go in depth if required Add links and other resources as. 27' which means 270ms rather than 27ms. modifiedon, GETDATE ()) = 0) But I need to select the yesterday. datediff function. We would like to show you a description here but the site won’t allow us. However then. For example, Snowflake supports the following values: YEAR, QUARTER, MONTH, WEEK, DAY, HOUR,. datediff¶. Found the solution -- I set a static value for the GENERATOR and then put a QUALIFY statement on it to limit the values to the first maxrange returned. There are certain use case scenarios when it is recommended to use the DATEDIFF function within the Snowflake cloud data warehouse which are as follows: If we want to find the difference between two dates in the form of days, years, or months. The documentation can be found here:. functions. One aproach to deal with division by zero is to use NULLIF. Accepts relevant date and time parts (see next section for details). datediff (part: str, col1: Column | str, col2: Column | str) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. Hello, The calendar table is used extensively in reporting to generate weekly / monthly /quarterly reports. Here's something slightly different from what the o. Hi @JustineMit - if an answer helps you, please upvote and/or accept it. Hi @JustineMit - if an answer helps you, please upvote and/or accept it. sql 명령 참조. Usage Notes¶. microsecond は、時、分、秒、および小数秒の最初の6桁を使用します。. 2 Answers. 다음 예에서 timestamp_type_mapping 매개 변수는 timestamp_ltz(현지 타임존)로 설정됩니다. Accepts relevant date and time parts (see next section for details). g. Dec 15, 2022 at 22:20. I have used the code contained below to create date and time scaffolds for several clients for various reasons, such as populating records between the “CreateDate” and “CloseDate” of a data point. snowflake. In the attached example, I created 'Days from Process A to Process B' to calculate the DateDiff but am unable to calculate an average due to the inability to further Aggregate. Then you try to use this number with the DATEADD function, and it expects to have a date instead. 複数の行が評価される場合（例: 入力が複数の行を含むテーブルの列名である場合）、値が秒. The number of rows backward from the current row from which to obtain a value. This allows, for example, choosing the N-th day in a year, which can be. When operating on a large quantity of data, gaps can appear in a sequence. Learn More >>When using convert_timezone() to convert timestamps with no timezone to my local time, the function outputs a timestamp like (I'm converting from timestamp with no time zone UTC to MST):Timestamp difference in Snowflake. SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. functions. How to create user defined function using variable in snowflake? Hot Network Questionsso you would expect to only get two rows if you use this logic in the filter, which is what happens. 123秒を返します。 microsecond は、時、分、秒、および小数秒の最初の6桁を使用します。小数秒は丸められません。 Snowflakeは、週に関連する特別な一連の日付関数（および同等のデータ部分）を提供し、その動作は DAYOFWEEKISO 、 WEEKISO 、 YEAROFWEEKISO の ISO 週のセマンティクスと一致しています。. functions. – string_expr or timestamp_expr or variant_expr or integer. content_copy. Query: CREATE OR REPLACE TABLE MY_DATE_DIMENSIONThe basic syntax of the DATEDIFF function is given below. We would like to show you a description here but the site won’t allow us. 1239') は1. If the value of Nweek = '201834' then the value of IDate is returned as '2018-08-20' If the value of Nweek =. -2. Pramit Marattha. Here are a few simple examples of using BETWEEN with numeric and string values:Unfortunately, at this moment Snowflake does not allow expressions in ADD COLUMN statements (only constant values) and does not allow adding a default value. The return value is always of type TIMESTAMP_TZ. Some time you expect the diff in "days" between 1. functions. MSSQL on the other hand does an implicit cast of '0' to DATE '1900-01-01' and returns the result in the requested date part. Use the Snowpark API to call system-defined functions, UDFs, and stored procedures. The value can be a literal or an expression. Alternative for DATEDIFF. Berechnet die Differenz zwischen zwei Datums-, Zeit- oder Zeitstempelausdrücken anhand der angeforderten Datums- oder Zeitkomponente. Para ambos DATEDIFF e sinal de menos: Os valores de saída podem ser negativos, por exemplo, -12 dias. Snowflake separates compute from storage, allowing for flexible pricing and configuration. 124秒ではなく、1. expr. Whereas DATEDIFF by default returns difference of dates in INT format. The function returns the result of subtracting the second argument from the third argument. Le signe moins ( -) peut également être utilisé pour soustraire des dates. select t. SQL Server Syntax DATEDIFF(datePart, date1, date2) The DATEDIFF() function in SQL Server has three required parameters:. In this article, Let us see a Spark SQL Dataframe example of how to calculate a Datediff between two dates in seconds, minutes, hours, days, and months using Scala language and functions like datediff(), unix_timestamp(), to_timestamp(),. The DATEDIFF code. I would use this: DECLARE @BegDate as date. How can get a list of all the dates between two dates (current_date and another date 365 days out). Stack Overflow. select t. functions. When date_or_time_part is week (or any of its variations), the output is controlled by the WEEK_START session parameter. So I got help to get started on this and it runs well. The parameter group bounds changes the way the join happens in a. DATEDIFF () function is used to subtract two dates, times, or timestamps based on the date or time part requested. The DATEDIFF command takes a datepart and returns the difference between two dates or timestamps. String concatenation will build '1' + ',' + '27'. Reports_Logs ( ProcessID int NOT NULL IDENTITY primary keyTO_DATE , DATE. highest, second-highest, etc. 小数秒は丸められません。. I've attached an example similar to what I'm trying to achieve. snowpark. I need to calculate the average DateDiff where the two dates are in separate data sources. Excluding only weekends doesn't work for business purposes. Is there any inbuilt function that provides the timestamp instead of computing the datediff every time? In both cases above the output timestamp is epoch timestamp corresponding to the CURRENT_DATE (which is the current time in the snowflake account time zone). 要求された日付または時刻の部分に基づいて、2つの日付、時刻、またはタイムスタンプ式の差を計算します。この関数は、3番目の引数から2番目の引数を減算した結果を返します。 マイナス記号（-）を使用して日付を減算することもできます。Why DATEDIFF() function in Snowflake works differently while getting date difference in weeks. date_expr. Data Superheroes. Sorry if I wasted anyone's time. Snowflake: DATEDIFF(‘day’, start, stop) AS days. datediff (part: str, col1: Column | str, col2: Column | str) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. Are you trying to get the first day of the previous month? If so, try this DATEADD( month, -1 , date_trunc('month', current_date()) ) DATEDIFF의 경우: date_or_time_expr1 및 date_or_time_expr2 는 날짜, 시간 또는 타임스탬프일 수 있습니다. The number of bytes if the input is BINARY. I usually us datediff(dd, l. ,DATEDIFF(SECOND, DATETIME_1, DATETIME_2) AS DIFF_SECONDS. microsecond uses the hour, minute, second, and first six digits of the fractional seconds. Note, that since DATEDIFF returns an integer value, the result also will be an integer. The data type of the variable is derived from the data type of the result of the evaluated expression. snowpark. functions. Datediff didn't work: DATEDIFF(hour,2,TO_DATE(substr(p. orderdate)) AS daysdiff FROM sales. Below is SQL Server:YEAR* / DAY* / WEEK* / MONTH / QUARTER¶. Oracle Database using Sql developer. datediff¶ snowflake. AS orderdate2 ,DATEDIFF("D", ord1. That would be: select t. I am using the query in Snowflake: select DATEDIFF(day,start_date ,end_date) as days ,start_date ,end_date from table1 It gives me no. Cognos will convert this to DATEDIFF but the arguments are reversed in the 2 functions. 0. So, the following snippet returns 119 ( 6 = 7th January 1990 ) SELECT DATEDIFF (year, '1900/01/07', '2019/05/15'); Share. Thanks, Rag. -- Get difference in days SELECT DATEDIFF ( dd, '2022-09-01', '2022-09-05'); # 4. 2021-06-10 12:07:04. If the datasource was previously pointing to SQL Server or DB2 and is now going to Snowflake, there might be some incorrect results when using the days_between. So this is really two parts, to know what year-quarter something is with respect to an offset, you just need to subtract the offset month, from the date you have and then year and quarter the adjusted date. SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) But based on my reading and some SQL Fiddle, it seems to output the start of "this week" minus 3 days. The DATEDIFF function will still work, but you'll want to make sure the input parameters are correct. approx_percentile_estimate. g. checkin. Snowflake Datediff ignores timezones. I want to create Calendar Table in Snowflake which has start and end date as dynamic dates. If either the input_expr or the scale_expr is NULL, the result is NULL. If the variant contains a date, the date value is preserved as is. DATEDIFF (date_part, date1, date2) Where, date_part parameter is the part of the date like day, month, and year, which you want to use in your computation. 0 would return 0, but DATEDIFF(second, start_date, end_date) / 3600. snowpark. 6. 000. select datediff (second, CURRENT_TIMESTAMP, fs. October 10, 2023. Each date value contains the century, year, month, day, hour, minute, second and milliseconds. These functions are alternatives to using the DATE_PART (or EXTRACT) function with the equivalent date part (see. snowpark. For example, you can use interval data type functions to add years, months, days, hours, etc to the timestamp variables. The later point it seems cannot be done with. Viewed 11k times. Can anybody help how can we pass dynamic dates in snowflake View/Table. Create an intermediate temporary table, e. List months between two dates in snowflake table. Snowflake is a complete SaaS offering that requires no maintenance. The * tells Snowflake to look at all columns, but you could have put just one column as it means the same thing. Otherwise, the current session time zone is used. value. BR. However, the functions above will count all the days between the two specified dates. What is SUBSTRING () Function in Snowflake? SUBSTRING () function helps to get the substring from a string by providing the starting index and length of the substring. Snowflake’s DATEDIFF function has the same syntax as SQL Server: SELECT DATEDIFF(datepart, startdate, enddate) FROM table_name; However, there are some differences in the supported datepart values. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. 5 is rounded to -1. The DateDiff function returns how many seconds, months, years - whatever interval you specify between the first date (here 0) and the second date (here the current date). Arguments. Tony Williams Tony Williams. 5 to 0), pass in 'HALF_TO_EVEN' for the rounding_mode argument. snowflake. This should be an integer. snowflake. Many applications use date functions to manipulate the date and time data types. You want to insert the data along with the current date. The function returns the result of. So the order should be always if deadline is NULL. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. CREATE TABLE t (id int, creation_date VARCHAR (19. functions. I want to run the same code again with different parameters and want. Get the field type for each column in a table. approx_percentile_combine. When using these operators: Make sure that each query selects the same number of columns. Result as Date — Image by Author Function 3: Date Difference. What is the best reusable way to calculate the total number of seconds that occurred on business days between two datetime values (ignoring weekends and federal holidays)? Here is a brief and simplified extract of my current dataset: All my users currently have a start time and end time for various actions they complete. What is the desired behavior?A number of seconds (if scale = 0 or is absent) or fractions of a second (e. Any fields using concatenation likely need to be modified. A possible workaround, especially if your data is not very large, is to create a new table with the exact schema you want and move the. datediff (part: str, col1: Column | str, col2: Column | str) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. So, i think, hive considers date + time difference but snowflake consider only date part and time part is ignored. @nehan it looks like you were able to solve your issue, that is so great! It would mean a lot if you can select the "Best answer" yourself to help others find the right answer faster. I'll jump straight to the code for those who like to see the answer first, and further down explain how it works. I'm trying to calculate an age value for our users based on their birthday, which one would expect to be a simple enough operation. snowflake. functions. For example if. I can convert the TZ on the timestamps, but that's undone by the time-only functions. datePart is the part of the date to return. approx_percentile_estimate. firstdate))) OVER. of days as: days start_date end_date 14 2022. , datediff (minute, p. Get the Average of a Datediff function using a partition by in Snowflake. ELSE 0 END – if the previous. date_from) = 1. There are certain use case scenarios when it is recommended to use the CURRENT_DATE function within the Snowflake cloud data warehouse which are as follows: You want to match the current date with column value to get the required output. Alias for DATEADD. functions. Fractional seconds are not rounded. Write resolution instructions: Use bullets, numbers and additional headings Add Screenshots to explain the resolution Add diagrams to explain complicated technical details, keep the diagrams in lucidchart or in google slide (keep it shared with entire Snowflake), and add the link of the source material in the Internal comment section Go in depth if required Add links and other resources as. 2. I want to be able to compare the date between the first record and any future records for that card id where that future record's legit = 0, and if the first record is within 10 days, show that record. I'm trying to figure out how to find "DATEDIFF" between several events in a data set for a specific value (Article No). This is how I was able to generate a series of dates in Snowflake. datediff. My stored procedure is static, meaning, I address the table X directly and I want it be a parameter that will be provided to stored procedureSnowflake supports a single DATE data type for storing dates (with no time elements). Based on Snowflake docs: Dynamically Creating a SQL Statement As stated in SQL Injection (in this topic), be careful to guard against attacks when using dynamic SQL. what I need is to expand their dates for each record, for example: id | date_start | date_end 1 | 2019-12-01 | 2019-12-05 2 | 2020-01-01 |. Take the max of that filtered list, then join back to the original data to get the status for the row with the max value. I want to find the time difference between two timestamps for each id . In most use cases, Snowflake correctly handles date and timestamp values formatted as strings. About; Products. DATEDIFF. snowpark. functions. Query and process data with a DataFrame object. In terms of Ingestion performance, Databricks provides strong Continuous and Batch Ingestion with Versioning. In certain cases, such as string-based comparisons or when a result depends on a different timestamp format than is set in the session parameters, we recommend explicitly converting. Actually, the marked answer originally produced wrong results for milliseconds 1 - 99: Example 1 second, 27 milliseconds: DATEDIFF % 1000 will return 27. Oracle: MONTHS_BETWEEN function returns the number of months between date1 and date2. start end), -- calculate the min of the two end. I am trying to get the same output in Snowflake, but cant figure out how to return a float. Need to break down a date field "DAY" to monthly and weekly wise in snowflake. Alias for DATEDIFF. Dec 15, 2022 at 23:25. timestamp_expr. I want the end result to be a date. approx_percentile_estimate. SELECT datediff(MS, '2013-06-30 23:59:59. This looks like the syntax for SQL Server, not Snowflake. TIMEDIFF. Collation Details¶. HOUR. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. snowpark. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. 2 days, but Snowflake will produce 1 because 2 is 1 more than 1. A function that could be interesting for Data Analysts and Data Scientists is the DATEDIFF function. In SQL Server here's a little trick to do that: SELECT CAST(FLOOR(CAST(CURRENT_TIMESTAMP AS float)) AS DATETIME) You cast the DateTime into a float, which represents the Date as the integer portion and the Time as the fraction of a day that's passed. Expand Post. Variables can be initialized in SQL using the SET command. sql. select datediff ( day, Date ('Tue Jan 01 1980 00:00:00 GMT-0800 (Pacific Standard Time)')::timestamp, Date ('Tue Jan 01 2020 00:00:00 GMT-0800 (Pacific Standard Time)')::timestamp ); The function you mentioned will return the difference in days between the two dates specified. From fetching the current timestamp to calculating date differences, we've got you covered. Supported date and time parts. This is the number of months you want to add. datediff(part: str, col1: Union[Column, str], col2: Union[Column, str]) → Column[source] Calculates the difference between two date, time, or timestamp columns based on the date or time part requested, and returns result of col2 - col1 based on the requested date or time part. The expression to be returned based on the specified offset. 1239') returns 1. date1 and date2 are the respective starting and ending dates for which you are about to find the difference. 44597. datediff (part: str, col1: ColumnOrName, col2: ColumnOrName) → Column [source] ¶ Calculates the difference between two date, time, or timestamp columns based on the date or time part requested. Usage Notes¶. Q&A for work. The function returns the result of subtracting the second argument from the third argument. Se um conjunto de carimbos de data/hora não tem um fuso horário especificado, então o. From Snowflake. EXTRACT. Oct 22, 2022. 1. Snowflake supports using string constants to specify fixed date, time, or timestamp values. DATEDIFF¶ Calculates the difference between two date, time, or timestamp expressions based on the date or time part requested. Start Date & End Date should be Min & Max dates of Sales Fact Table. Specifies the day of week used to calculate the date for the previous day. As you have pointed out, and it is refenced in the linked below, DATEDIFF does not guarantee that the full number of the specified time units passed between 2 datetime values. This gist creates a function in Postgres that implements the DATEDIFF function found in Snowflake, BigQuery, and Redshift.